5+2.5+3.5+...+8.5+9.5
=5.(1+2+3+...+8+9)
=5.\(\frac{\left(9+1\right).9}{2}\)
=5.45
=225
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5+2.5+3.5+...+8.5+9.5
=5.(1+2+3+...+8+9)
=5.\(\frac{\left(9+1\right).9}{2}\)
=5.45
=225
\(P=\dfrac{2.5^{22}-9.5^{20}}{25^{10}}:\dfrac{5\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
Tìm x,biết
A) (-3)^2x=9^5
B) 9.5^ x-3=6.5^6+3.5^6
C) 5^x+4-3.5^x+3=5^11.2
D) 3^x+2+4.3^x+1=7.3^6
E) 5^x+3=10^5.6^3:4^4.3^3
Tìm x, biết:
\(5^{x-11}-2.5^2=3.5^3\)
5^x+4-3.5^x-3=2.5^11
5^x+4-3.5^x-3=2.5^11
5^x+4-3.5^x-3+2.5^11
5^x+4-3.5^x-3+2.5^11
Tìm x
Tìm x, biết:
a)2.52.32+{[2.53-(5.x+4).5}}:(22.3.5)}=453
b)\(|x-\frac{1}{3}|=2\)