`5/2-(x+1/2)=3-(5/2+1/3)`
`=>5/2-x-1/2=3-5/2-1/3`
`=>2-x=3-5/2-1/3`
`=>2-3+5/2+1/3=x`
`=>x=-1+5/2+1/3`
`=>x=3/2+1/3=11/6`
Vậy `x=11/6`
\(\dfrac{5}{2}-\left(x+\dfrac{1}{2}\right)=3-\left(\dfrac{5}{2}+\dfrac{1}{3}\right)\\ \dfrac{5}{2}-\left(x+\dfrac{1}{2}\right)=\dfrac{1}{6}\\ x+\dfrac{1}{2}=\dfrac{5}{2}-\dfrac{1}{6}\\ x+\dfrac{1}{2}=\dfrac{7}{3}\\ x=\dfrac{7}{3}-\dfrac{1}{2}\\ x=\dfrac{11}{6}\)
5/2-(x+1/2)=3-17/6
5/2-(x+1/2)=1/6
x+1/2=5/2-1/6
x+1/2=7/3
x=7/3-1/2
x=11/6
Vậy x =11/6