\(-\dfrac{5}{12}+\dfrac{3}{4}=\dfrac{-5}{12}+\dfrac{9}{12}=\dfrac{1}{3}\)
\(-\dfrac{5}{12}+\dfrac{3}{4}=\dfrac{-5}{12}+\dfrac{9}{12}=\dfrac{1}{3}\)
-5/12+0,75=?
Thực hiện phép tính:
\(d,\dfrac{-5}{12}+0,75\)
\(e,\dfrac{5}{7}.12\dfrac{1}{2}-\dfrac{5}{7}.5\dfrac{1}{2}\)
\(\dfrac{0,375-0,3+\dfrac{3}{11}+\dfrac{3}{12}}{-265+0,5-\dfrac{5}{11}-\dfrac{5}{12}}\)+\(\dfrac{1,5+1-0,75}{2,5+\dfrac{5}{3}-1,25}\)
-5
____ + 0,75
12
\(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
\(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,265+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-\frac{5}{4}}\)
\(A=\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)
Tính \(P=2005:\left(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}.\frac{2,5+\frac{5}{3}-1,25}{1,5+1-0,75}\right)\)
Tính:
\(A=\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)