Question

5 tính tổng sau bằng cách hợp lý. a,A = 4/3x6 + 4/6x9 + ... + 4/18x21

Answer 1

A = \(\dfrac{4}{3\times6}\) + \(\dfrac{4}{6\times9}\) + ......+ \(\dfrac{4}{18\times21}\)

A = \(\dfrac{4}{3}\) \(\times\) ( \(\dfrac{3}{3\times6}\) + \(\dfrac{3}{6\times9}\)+......+ \(\dfrac{3}{18\times21}\))

A = \(\dfrac{4}{3}\) \(\times\) ( \(\dfrac{1}{3}\) - \(\dfrac{1}{6}\) + \(\dfrac{1}{6}\) - \(\dfrac{1}{9}\)+.....\(\dfrac{1}{18}\) - \(\dfrac{1}{21}\))

A = \(\dfrac{4}{3}\) \(\times\) ( \(\dfrac{1}{3}\) - \(\dfrac{1}{21}\))

A = \(\dfrac{4}{3}\)\(\times\) \(\dfrac{2}{7}\)

A = \(\dfrac{8}{21}\)