\(5^{2x-3}-25^2=5^{2.3}\)
\(5^{2x-3}-\left(5^2\right)^2=5^6\)
\(5^{2x-3}-5^4=5^6\)
-> 2x - 3 - 4 = 6
2x - 3 = 4 + 6
2x - 3 = 10
2x = 10 + 3
2x = 13
x = \(\frac{13}{2}\)
\(5^{2x}-3-25^2=3.5^2\)
\(25^x-25^2=3\left(5^2+1\right)\)
\(\Leftrightarrow25^x=78\)
Vậy........