\(4x^2-8x-16=0\)
<=> \(x^2-2x-4=0\)
<=> \(\left(x-2\right)^2=0\)
<=> \(x=2\)
\(|x-4|+3x=5\)
<=> \(|x-4|=5-3x\)
<=> \(x-4=5-3x\) ( h ) \(x-4=-5+3x\)
<=> \(4x=9\left(h\right)-2x=-1\)
<=> \(x=\frac{3}{2}\left(h\right)x=\frac{1}{2}\)
chúc bn học tốt
\(4x^2-8x-16=0\)
<=> \(x^2-2x-4=0\)
<=> \(\left(x-2\right)^2=0\)
<=> \(x=2\)
\(|x-4|+3x=5\)
<=> \(|x-4|=5-3x\)
<=> \(x-4=5-3x\) ( h ) \(x-4=-5+3x\)
<=> \(4x=9\left(h\right)-2x=-1\)
<=> \(x=\frac{3}{2}\left(h\right)x=\frac{1}{2}\)
chúc bn học tốt
Phân tích đa thức thành nhân tử
a (8x-11)^2-(4x-5)(2x-3)-75
b (3x-14)(x-5)^2 (3x-16)-8
c (x^2+6x-16)(x^2+4x-21)-144
a) \(\frac{7}{8x}+\frac{5-x}{4x^2-8x}=\frac{x-1}{2x^2-4x}+\frac{1}{8x-16}\)
b) 3x.|x+1|−2x|x+2|=12
Tìm x biết
1,(2x+5)(2x-7)-(-4x-3)^2=16
2,(8x-3)(3x+2)-(4x+7)(x+4)=(2x+1)-(5x-1)
Tìm x biết :
a) (3x³ + x² – 13x + 5) : (x² + 2x – 1) = 10
b) (x⁴ – 2x² – 8) : (x – 2) = 0
c) (x²-4x) : (x²-8x+16) = 0
Tìm x biết:
a) (3x³ + x² – 13x + 5) : (x² + 2x – 1) = 10
b) (x⁴ – 2x² – 8) : (x – 2) = 0
c) \(\dfrac{x^2-4x}{x^2-8x+16}\)= 0
giải phương trình: x-1/2x^2-4x - 7/8x = 5-x/4x^2-8x - 1/8x-16
Giai PT a, 6/x^2-1 + 5 = 8x-1/4x+4 - 12x-1/4-4x
b, 2x+1/2x-1 - 2x-1/2x+1 = 8/4x^2 -1
c, 3/2x-16 + 3x-20/x-8 + 1/8 = 13x-102/3x-24
d, x+4/x^2-3x+2 - x+1/x^2 -4x+3 = 2x+5/x^2-4x+3
phân tích đa thức ->nhân tử:
a)2x2+4x-70
b)x3-5x2+8x-4
c)x2-10+16
rút gọn:
(8x-8x3-10x2+3x4-5):(3x2-2x+1)
tìm x biết
a, (x^2-4x+16)(x+4)-x(x+1)(x+2)+3x^2=0
b, (8x+2)(1-3x)+(6x-1)(4x-10)=-50