\(\Leftrightarrow4x^2-4x^2+6x-10x+15=7\)
=>4x=-8
hay x=-2
`4x^2-(2x+5)(2x-3)=7`
`<=> 4x^2 - [ 2x(2x-3) + 5(2x-3) ] =7`
`<=> 4x^2 - [4x^2 -6x+10x -15] =7`
`<=> 4x^2 - 4x^2 +4x +15 =7`
`<=>4x +15 =7`
`=> 4x = 7-15 =-8`
`=> x =-8/4 =-2`
Vậy `S={-2}`
\(\Leftrightarrow4x^2-4x^2+6x-10x+15=7\)
=>4x=-8
hay x=-2
`4x^2-(2x+5)(2x-3)=7`
`<=> 4x^2 - [ 2x(2x-3) + 5(2x-3) ] =7`
`<=> 4x^2 - [4x^2 -6x+10x -15] =7`
`<=> 4x^2 - 4x^2 +4x +15 =7`
`<=>4x +15 =7`
`=> 4x = 7-15 =-8`
`=> x =-8/4 =-2`
Vậy `S={-2}`
Tìm x biết
1.(x+3)2-(x+2).(x-2)=4x+17
2.(2x+1)2-(4x-1).(x-3)-15=0
3.(2x+3).(x-1)+(2x-3).(1-x)=0
4.2(5x-8)-3(4x-5)=4(3x-4)+11
5.(3x-1).(2x-7)-(1-3x).(6x-5)=0
Tìm x biết
1. 2(5x-8)-3(4x-5)=4(3x-4)+11
2. (2x+1)2-(4x-1).(x-3)-15=0
3. (3x-1).(2x-7)-(1-3x).(6x-5)=0
A, (x-2)^2=4x^2+4x+1 B, 25x^2-9=0 C, (2x-1)^2+(x+3)^2-5(x+7)(x-7)=0 D, (2x+1)(x-4)-2(x-3)^2=8 E, (3x-1)^2=(5-x)^2
Rút gọn :
1. (2x-5)(3x+1)-(x-3)^2+(2x+5)^2-(3x+1)^3
2. (2x-1)(2x+1)-3x-2)(2x+3)-(x-1)^3+(2x+3)^3
3. (x-2)(x^2+2x+4)-(3x-2)^3+(3x-4)^2
4. (7x-1)(8x+2)-(2x-7)^2-(x-4)^3-(3x+1)^3
5. (5x-1)(5x+1)-(x+3)(x^2-3x+9)-(2x+4)^2-(3x-4)^2+(2x-5)^3
6. (4x-1)(x+2)-(2x+5)^2-(3x-7)^2+(2x+3)^3=(3x-1)^3
Bài 3: Giải các phương trình sau bằng cách đưa về dạng ax +b =0 ( giải chi tiết )
a)7 – x = -2x +3
b) 2 (3x +1) = -2x +5
c) 5x + 2(x – 1) = 4x + 7.
d) 10x^2 - 5x(2x + 3) = 15
a)(2x-1)^2+(x+3)^2-5(x+7)(x-7)=0
b)(x+2)(x^2-2x+4)-x(x^2+2)=15
c)(x+3)^3-x(3x+1)^2+(2x-1)(4x^2-2x+1)=28
d)(x^2-1)^3-(x^4+x^2+1)(x^2-1)=0
a, 6x^3-6x=0
b, 2x(3x+7) -6x^2=28
c, 2(4x+4)-5(x-3)=0
a)(2x-1)^2+(x+3)^2-5(x+7)(x-7)=0
b)(x+3)^3-x(3x+1)^2+(2x-1)(4x^2-2x+1)=28
c)(x+2)(x^2-2x+4)-x(x^2+2)=15
d)(x^2-1)^3-x^4+x^2+1)(x^2-1)=0
giải pt sau
g) 11+8x-3=5x-3+x
h)4-2x+15=9x+4-2x
g)\(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=\dfrac{5}{3}+2x\)
h)\(\dfrac{x+4}{5}-x+4=\dfrac{4x+2}{5}-5\)
i)\(\dfrac{4x+3}{5}-\dfrac{6x-2}{7}=\dfrac{5x+4}{3}+3\)
k) \(\dfrac{5x+2}{6}-\dfrac{8x-1}{3}=\dfrac{4x+2}{5}-5\)
m) \(\dfrac{2x-1}{5}-\dfrac{x-2}{3}=\dfrac{xx+7}{15}\)
n)\(\dfrac{1}{4}\left(x+3\right)=3-\dfrac{1}{2}\left(x+1\right)-\dfrac{1}{3}\left(x+2\right)\)
p)\(\dfrac{x}{3}-\dfrac{2x+1}{6}=\dfrac{x}{6}-x\)
q)\(\dfrac{2+x}{5}-0,5x=\dfrac{1-2x}{4}+0,25\)
Tìm x, biết:
a) (2x + 3)3 - (2x + 1) . (2x - 1) = 22
b) (4x + 3) . (4x - 3) - (4x - 5)2 = 46
c) (3x + 4)2 + (5x - 2)2 - 2x. (17x - 1) = 10
d) (4x -1)2 - (4x + 3)2 - (x - 3) = 4