=>(2^x)^2-12*2^x+32=0
=>(2^x-4)(2^x-8)=0
=>x=3 hoặc x=2
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Các câu hỏi tương tự
P = (x + 1)(x + 2)(x + 3)(x + 4) - 32
Q = x2 - 2xy + y2 + 3x - 3y + 1
R = 4x2 + \(\dfrac{1}{x^2}\)-20 (x>0)
Tìm x biết :
a) x2\(-\)4x+4=25
b) \(\dfrac{x-17}{1990}\)+\(\dfrac{x-21}{1986}\)+\(\dfrac{x+1}{1004}\)=4
c) 4x\(-\)12.2x+32=0
P = (x + 1)(x + 2)(x + 3)(x + 4) - 32
Q = x2 - 2xy + y2 + 3x - 3y + 1
R = 4x2 + \(\dfrac{1}{x^2}\)
BÀi 5
a) x^2 - 12 x + 11 = 0
b) 4x^2 - 4x - 3 = 0
c) 4x^2 - 12x - 7 = 0
d) x^3 - 6x^2 = 8 - 12x
TÌm x
a) x^2 - 12x +11 = 0
b) 4x^2 - 4x - 3 = 0
c) 4x^2 - 12x - 7 = 0
d) x^3 - 6x^2 = 8 - 12x
I : Tìm x , y
a) x^2+y^2-2x+4y+5=0
b) 4x^2+y^2-4x-6x+10=0
c) 5x^2-4xy+y^2-4x+4=0
d)2x^2-4xy+4y^2-10x+25=0
help me
Tìm x biết:
4x2 - 6x = 0
b) 4x2 + 4x = -1
c) 5x2 + x = 0
d) x3 - 5x = 4x2
3x(x-2) = x-2
x3 - 16x = 0
tìm x ,biết :
a, x^2-3x = 0
b,x^5-9x = 0
c, ( x^3-4x^2) - ( x-4) = 0
d, (4x^2-25)^2- 9 ( 2x - 5 )^2= 0
Tìm x
a) x^3 - 16x = 0
b) x^4 - 2x^3 + 10x^2 - 20x = 0
c) (2x - 3 )^2 = (x+5)^2
d) x^2(x-1) - 4x^2 + 8x - 4 = 0
e) x^2 + 4x + 3 = 0
f) x^3 - x^2 = 4x^2 - 8x + 4
g) 2(x+3) - x^2 - 3x = 0
Giải PT: \(\dfrac{5}{x^2-4x+5}-x^2+4x-1=0\)