b: \(=\left(x-y\right)^2+3\left(x-y\right)+1\)
\(=\left(x-y+\dfrac{3}{2}\right)^2-\dfrac{5}{4}>=-\dfrac{5}{4}\)
Dấu '=' xảy ra khi x-y=-3/2
=>x=y-3/2
c: \(4x^2+\dfrac{1}{x^2}\ge2\sqrt{4x^2\cdot\dfrac{1}{x^2}}=4\)
Dấu '=' xảy ra khi \(4x^4=1\)
=>x4=1/4
hay \(x=\pm\dfrac{\sqrt{2}}{2}\)