Question

49/2 - 1/2 - 1/4 - 1/8 - 1/16 - 1/32

Answer 1

= \(\dfrac{49}{2}-\dfrac{1}{2}-\dfrac{1}{4}-\dfrac{1}{8}-\dfrac{1}{16}-\dfrac{1}{32}\)

= \(\dfrac{784}{32}-\dfrac{16}{32}-\dfrac{8}{32}-\dfrac{4}{32}-\dfrac{2}{32}-\dfrac{1}{32}\)

= \(\dfrac{753}{32}\)

Answer 2

       A =       \(\dfrac{49}{2}\) - \(\dfrac{1}{2}\) - \(\dfrac{1}{4}\) - \(\dfrac{1}{8}\) - \(\dfrac{1}{16}\) - \(\dfrac{1}{32}\)

A \(\times\) 2  = 49 - 1 - \(\dfrac{1}{2}\)  - \(\dfrac{1}{4}\) - \(\dfrac{1}{8}\) - \(\dfrac{1}{16}\)

A \(\times\) 2  - A = 48 - \(\dfrac{49}{2}\) + \(\dfrac{1}{32}\)

            A  =   \(\dfrac{1536}{32}\) - \(\dfrac{784}{32}\) + \(\dfrac{1}{32}\)

             A = \(\dfrac{753}{32}\)