nhớ tick đúng đó nha
4.(3x-1)-2.(5-3x)=12
<=>12x-4-10+6x=12
<=>18x-14=12
<=>18x=26
<=>x=13/9
4.2x-2.2x=12
(4-2).(2x.2x)=12
2.4x=12
4x=12:2
4x=6
x=6:4
x=\(\frac{6}{4}\)
Giải phương trình:
a) \(\dfrac{x+5}{3x-6}-\dfrac{1}{2}=\dfrac{2x-3}{2x-4}\)
b) \(\dfrac{12}{1-9x^2}=\dfrac{1-3x}{1+3x}-\dfrac{1+3x}{1-3x}\)
c) \(\dfrac{x+1}{x-2}-\dfrac{5}{x+2}=\dfrac{12}{x^2-4}+1\)
Giải phương trình:
a) \(\dfrac{12}{1-9x^2}=\dfrac{1-3x}{1+3x}-\dfrac{1+3x}{1-3x}\)
b) \(\dfrac{x+1}{x-2}-\dfrac{5}{x+2}=\dfrac{12}{x^2-4}+1\)
Giải phương trình:
a) \(\dfrac{12}{1-9x^2}=\dfrac{1-3x}{1+3x}-\dfrac{1+3x}{1-3x}\)
b) \(\dfrac{x+1}{x-2}-\dfrac{5}{x+2}=\dfrac{12}{x^2-4}+1\)
Giải phương trình:
a) 5 + 96/x2-16 = 2x-1/x+4 - 3x-1/4-x
b) 3x+2/3x-2 - 6/2+3x = 9x2/9x2-44
c) 1/x-1 + 1/x+1 = 2/x+2
d) x+1/x-2 - 5/x+2 = 12/x2-4 + 1
Mọi người check xem đúng không:
<=>x(3x+2)+(x+1)^2 - (2x - 5)(2x+5)= -12
<=>3x^2 + 2x + (x+1)^2 - 2x^2 - 5^2= -12
<=>(3x^2 - 2x^2) + [ (x +1)^2 -5^2] + 2x = -12
<=>(3x - 2x)(3x + 2x)+ (x+1-5) (x+1+5) + 2x = -12
=> 3x - 2x = -12 ; 3x+2x = -12 ; x+1+5 = -12 ; x+1-5 = -12 hoặc 2x = -12
=> x = -12 ; 5x =-12 ; x+ 6 = -12 ; x -4 = -12 hoặc x = -12: 2
=> x= -12 ; x = -12:5; x = -12 :6; x = -12 + 4 hoặc x= -6
=> x= -12 x = -12/5; x = -2 ; x = -8 hoặc x = -6
Mọi người check xem đúng không:
<=>x(3x+2)+(x+1)^2 - (2x - 5)(2x+5)= -12
<=>3x^2 + 2x + (x+1)^2 - 2x^2 - 5^2= -12
<=>(3x^2 - 2x^2) + [ (x +1)^2 -5^2] + 2x = -12
<=>(3x - 2x)(3x + 2x)+ (x+1-5) (x+1+5) + 2x = -12
=> 3x - 2x = -12 ; 3x+2x = -12 ; x+1+5 = -12 ; x+1-5 = -12 hoặc 2x = -12
=> x = -12 ; 5x =-12 ; x+ 6 = -12 ; x -4 = -12 hoặc x = -12: 2
=> x= -12 ; x = -12:5; x = -12 :6; x = -12 + 4 hoặc x= -6
=> x= -12 x = -12/5; x = -2 ; x = -8 hoặc x = -6
1.Tìm x
a) 5.(x^2-3x+1)+x.(1-5x)=x-2
b)3x.\(\left(\frac{4}{3}+1\right)\)-4x.(x-2)=10
c)12x^2-4x.(3x-5)=10x-17
d) 4x(x-5)-7x.(x-4)+3x^2=12
1/ \(\dfrac{x+4}{4}+\dfrac{3x-7}{5}=\dfrac{7x+2}{20}\)
2/ \(\dfrac{x}{6}+\dfrac{1-3x}{9}=\dfrac{-x+1}{12}\)
3/ \(\dfrac{x-3}{3}-\dfrac{x+2}{12}=\dfrac{2x-1}{4}\)
4/ \(\dfrac{x-2}{4}-\dfrac{2x+3}{3}=\dfrac{x+6}{12}\)
5/ \(\dfrac{2x-1}{12}-\dfrac{3-x}{18}=\dfrac{-1}{36}\)
a,4x-8/2x2+1=0 b,x2-x-6/x-3=0 c,x+5/3x-6-1/2=2x-3/2x-4 d,12/1-9x2=1-3x/1+3x-1+3x/1-3x
