4 x 51 x 7 + 2 x 86 + 7 + 12 x 2 x 7
= 2 x 7 x 2 x 51 + 2 x 2 x 7 x 43 + 2 x 2 x 7 x 6
= 2 x 2 x 7 x ( 51 + 43 + 6 )
= 28 x 100
= 2800
4 x 51 x 7 + 2 x 86 x 7 + 12 x 2 x 7
= 2 x 2 x 51 x 7 + 2 x 2 x 7 x 43 + 2 x 2 x 7 x 6
= 2 x 2 x 7 x ( 51 + 43 + 6)
= 28 x 100
= 2800
\(\text{Ta có: 4 x 51 x 7 + 2 x 86 x 7 + 12 x 2 x 7
}\)
\(\text{= 2 x 2 x 51 x 7 + 2 x 2 x 7 x 43 + 2 x 2 x 7 x 6}\)
\(\text{= 2 x 2 x 7 x ( 51 + 43 + 6)
}\)
\(\text{= 28 x 100 = 2800}\)
4 x 51 x 7 + 2 x 86 + 7 + 12 x 2 x 7
= 2 x 7 x 2 x 51 + 2 x 2 x 7 x 43 + 2 x 2 x 7 x 6
= 2 x 2 x 7 x ( 51 + 43 + 6 )
= 28 x 100
= 2 800
Vậy: 4 x 51 x 7 + 2 x 86 x 7 + 12 x 2 x 7 = = 2 800