Question

(3x+4)^2=3^2+2^3+83

Answer 1

\((3x+4)^2=3^2+2^3+83\)

\((3x+4)^2 = \)\(9 + 8 + 83\)

\(( 3 x + 4 ) ^2 = 100\)

\(( 3 x + 4 ) ^2 = 10 ^2\)

\(3 x + 4 = 10\)

\(3x=10-4\)

\(3x=6\)

\(x=6:3=2\)

 

 

Answer 2

`(3x+4)^2=3^2+2^3+83`

`(3x+4)^2=100`

`<=> (3x+4)^2=(+-10)^2`

`<=>[(3x+4=10),(3x+4=-10):}`

`<=>[(x=2),(x=-14/3):}`

Answer 3

$(3x+4{}^{}={}^{}+{}^{}+83$

$(3x+4{}^{}=$$9+8+83$

$(3x+4{}^{}=100$

$(3x+4{}^{}={}^{}$

$3x+4=10$

$3x=10-4$

$3x=6$

$x=6:3=2$