\(\left[3\cdot\left(x+2\right):7\right]\cdot4=120\)
\(\Rightarrow3\left(x+2\right):7=30\)
\(\Rightarrow3\left(x+2\right)=210\)
\(\Rightarrow x+2=70\)
\(\Rightarrow x=68\)
Vậy x=68
[ 3 . ( x + 2 ) : 7 ] . 4 = 120
3 . ( x + 2 ) : 7 = 30
3 . ( x + 2 ) = 210
x + 2 = 70
x = 68
Nhớ li ke mk nha
[3x(x+2):7] x 4 = 120
[3x(x+2):7] = 120 : 4
[3x(x+2):7] = 30
3 x (x+2) = 30 x 7
3 x (x+2) = 210
x+2 = 210 : 3
x+2 = 70
x = 70 - 2
x = 68
[3×(x+2)÷7]×4=120
3x(x +2) :7 =120 : 4=30
(x +2) :7 = 30 :3 =10
x +2 =10 x 7= 70
x = 70 - 2
x =68
nếu đúng k mình nha các bạn
[3(x + 2) : 7] . 4 = 120
=> 3(x + 2) : 7 = 120 : 4
=> 3(x + 2) : 7 = 30
=> 3(x + 2) = 30 . 7
=> 3(x + 2) = 210
=> x + 2 = 210 : 3
=> x + 2 = 70
=> x = 70 - 2
=> x = 68
Vậy x = 68