(3^x)^2=1/243.3^3
(3^x)^2=1/9
3x=1/3 hoặc 3x=-1/3
Suy ra x=1/9 hoặc x=-1/9
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TÌM X, BIẾT:
a) 3 . ( 1/2 - x ) + 1/3 = 7/6 - x
b) 4 . ( 1/2 - x ) - 5 . ( x - 3/10 ) = 7/4
c) -3/2 . ( 4/5 - 2/3 ) + x = 4 . ( x - 1/2 )
d) 2 . ( 3/2 - x ) - 1/3 = 7x - 1/4
e) 1/5 . ( -3/5 -10 ) + 5x = x - 2/3
f) -3/2 . ( 5 - 1/6 ) + 4 . ( x - 1/2 ) = 1
~ PLEASE HELP ME ~
Tìm số hữu tỉ x biết
a) 2/3.x-2/5=1/2.x-1/3
b) 1/3.x+2/5(x+1)=0
c) 2/3-1/3(x-3/2)-1/2(2x+1)=5
d) 11/5-(7/9-x).3/8=61/90+x/3
a, |x-1/2|=|3|
b, 2|x-1|+3|x-1|=5
c, |-2/3|.|2x-1|=4/3.|x-1|+1
d, |x-1|-x=-1
e, |3x-2|=|x-1|
f,|2x-1|+2x=1
g, 2|x-1/2|=|x+1|
h, 3|x-1/3|+5|3/x-1/5|=2
(x+3)x+1=(x+3)x+2
(x-1)x+=(x-1)x+2
(2x-1)2=(x-3)2
Xem chi tiết
1/ 3 x (x - \(\dfrac{1}{2}\)) - 3 x (x - \(\dfrac{1}{3}\)) - (x - \(\dfrac{1}{2}\)) = 0
2/ \(\dfrac{-2x+1}{3}\) + \(\dfrac{1}{2}\) = \(\dfrac{-1}{3}\)
Thu gọn đa thức:C=5\(x^3\)\(y^2\)+3\(x^2\)\(y^3\) \(\dfrac{1}{3}\) \(x^4\) \(y^5\) - \(\dfrac{1}{7}\)+\(\dfrac{1}{2}\) \(x^2\)\(y^3\) - 3\(x^4\) \(y^5\)+ \(\dfrac{1}{3}\)-4\(x^3\) \(y^2\)
Xem chi tiết
1 tìm x biết
a 1/3+1/2:x=1/5
b 1/3.x +2/5.(x+1)=0
c 11/12-(2/5+x)=2/3
d 2/3-1/3.(x-3/2)-1/2.(2.x+1)=5
e (x+1/2).(x-3/4)=0
giúp mình với nhé
a,1/2(x-4)-1/4(x-4/3)=2(x-1/2)
b, 3/4-(x-1/2)^2=-11/2
c,3/16+1/1/16.(x-2/3)^2=3/4
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TÌM X
câu 1: (1/3 + 1/6) . 2^x+3 - 2^x = 2^22 - 2^20
câu 2: (1/2-1/6).3^x+3^x+2=3^16+3^13
câu 3: (1/2 - 1/6) . 3^x+4 - 4 . 3^x = 3^16 - 4 . 3^13
mình cần gấp. mn lm ơn giúp mifh vs ạ. !!!huhuhu
Tìm x
(3^2-2^3)x+3^2.2^2=4^2.3
x^5-x^3=0
(x-1)^2+(-3)^2=5^2.(-1)^100
(2x-1)^2-(2x-1)=0