\(3x\left(x-2\right)-3\left(x^2-4\right)=0\\ =>3x\left(x-2\right)-3\left(x-2\right)\left(x+2\right)=0\\ =>\left(x-2\right)\left[3x-3\left(x+2\right)\right]=0\\ =>\left[{}\begin{matrix}x-2=0\\3x-3x-6=0\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=2\\-6=0\left(voli\right)\end{matrix}\right.\\ =>x=2\)
\(3x\left(x-2\right)-3x^2+12=0\\ \Leftrightarrow3x\left(x-2\right)-3\left(x^2+4\right)=0\\ \Leftrightarrow3x\left(x-2\right)-3\left(x+2\right)\left(x-2\right)=0\\\Leftrightarrow \left(3x-3\right)\left(x+2\right)\left(x-2\right)=0\\ \Leftrightarrow\left\{{}\begin{matrix}3x-3=0\\x+2=0\\x-2=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=1\\x=-2\\x=2\end{matrix}\right.\)
3x(x−2)−3(x2−4)=0=>3x(x−2)−3(x−2)(x+2)=0=>(x−2)[3x−3(x+2)]=0=>[x−2=03x−3x−6=0=>[x=2−6=0(voli)=>x=2
