`(3x-3)^2`
`=(3x)^2 - 2.3x.3+3^2`
`=9x^2 - 18x+9`
⇒(3x−3)2(3x-3)2
⇔(3x)2−2.3x.3+32
⇒9x2−18x+9
kết quả của phép nhân 3x(x^2+2x-1) là:
A.3x^3+5x^2-3x
B.3x^2+6x^3-3x
C.3x^3-3x^2+6x
D.3x^3+6x^2-3x
Tính :
B=(x-3)3-(x+3).(x2-3x+9)+(3x-1).(3x+1)
C=(3x+2)3-18x.(3x+2)+(x-1)3-28x3+3x.(x-1)
Tìm x:
a.x^3-3x^2-1=-3x-8
b.x^3+3x^2=26-3x
c.(2x-3)^3-9(x+2)^3=-x^3-99
d.(x+1)^3+2(x-2)^3=3x(x-1)^2-15
B=(x-3)3-(x+3).(x2-3x+9)+(3x-1).(3x+1)
C=(3x+2)3-11818x18x .(3x3x+2)+(x-1)3 - 28x3+3x.(x-1)
Rút gọn các biểu thức sau:
a,(3x+1)^2-2(3x+1)(3x-5)+(3x-5)^2
b,(3x^2-y)^2
c,(3x+5)^2+(3x-5)^2-(3x+2)(3x-2)
d,2x(2x-1)^2-3x(x+3)(Õ-3)-4x(x+1)^2
e,(x-2)(x^2+2x+4)-(x+1)^2+3(x-1)(x+1)
f,(x^4-5x^2+25)(x^2+5)-(2+x^2)^2+3(1+x^2)^2
P=(x+3)^3-x.(3x+1)^2+(2x+1)(4x^2-2x+1)-3x^2
Q=(x-3)^3-(x-3)(x^2+3x+9)+6(x+1)^2+3x^2
d) (3x – 5)(7 – 5x) – (5x + 2)(2 – 3x) = 4 g) 3(2x - 1)(3x - 1) - (2x - 3)(9x - 1) =0 j) (2x – 1)(3x + 1) – (4 – 3x)(3 – 2x) = 3 k) (2x + 1)(x + 3) – (x – 5)(7 + 2x) = 8 m) 2(3x – 1)(2x + 5) – 6(2x – 1)(x + 2) = - 6
4x(5x − 2) 7x Ä 3x 2 − 6x + 2ä b) c) 2x(3x + 2) + (4x + 3)(2x − 1) 3x 3 y 2 : x 2 d) Ä x 3 + 4x 3 − 6x 2 ä : 4x 2 e) Ä 3x 2 − 6x ä f) : (2 − x) Ä 6x 2 + 13x − 5 ä g) : (2x + 5) Ä x 3 − 3x 2 + x − 3 ä h) : (x − 3)
3x^2(x^3-3x^2+1)
=3x^2.x^3+3x^2.(-3x^)+3x^2.1
=3x^5-9x^4+3x^2
mấy bạn ơi sao ra 3x^5-9x^4 vậy chỉ mk với mình cần gấp ạ
Rút gọn
a, (x-2).(3x-1).(3x+1)-2x.(4x-3)^2
b, ( 5x-7)^2 - ( 4x -3).(2x+3)^2- (x-3).(3x^2-5)
c, (2-5x)^2-4x.(3x+1)^2-(x-3).(x+3)
