\(3\left(x-2\right)^2-25=2=>3\left(x-2\right)^2=27=>\left(x-2\right)^2=\frac{27}{3}=9=3^2=\left(-3\right)^2\)
\(=>\orbr{\begin{cases}x-2=3\\x-2=-3\end{cases}=>\orbr{\begin{cases}x=5\\x=-1\end{cases}}}\)
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\(3\left(x-2\right)^2-25=2\)
\(=>3\left(x^2-4x+4\right)-25=2\)
\(=>3x^2-12x+12-25=2\)
\(=>3x^2-12x-13=2\)
\(=>3x^2-12x-15=0\)
\(=>\left(x-5\right)\left(x+1\right)=0\)
\(=>\orbr{\begin{cases}x-5=0\\x+1=0\end{cases}=>\orbr{\begin{cases}x=5\\x=-1\end{cases}}}\)
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