=>12x+8 chia hết cho 4x+1
=>12x+3+5 chia hết cho 4x+1
=>\(4x+1\in\left\{1;-1;5;-5\right\}\)
=>\(x\in\left\{0;-\dfrac{1}{2};1;-\dfrac{3}{2}\right\}\)
Timf `x`:
`(x - 2)/3 = (x + 1)/4`
`(x - 2) . 4 = (x + 1) . 3`
`<=> 4x - 8 = 3x + 3`
`<=> 4x - 3x = 3 + 8`
`<=> (4 - 3)x = 11`
`=> x = 11`
B) 17X - ( -16X - 37 ) + 2x + 43
C) -2x -3.( x-17) = 34 -2 (-2x +25)
D) 17x+ 3. ( -16x -37) = 2x +43 -4x
E) {- 3x +2. [45 - x-3 (3x + 7) - 2x] + 4x} =55
F) -103 - 57 : [ -2 ( 2x -1 )2 - ( -9 )0 ] - 106
G) -2x + 3. { 12-2 [ 3x - ( 20 + 2x ) - 4x ] + 1} = 45
(2x+3) chia hết (3x+1)
(3x+2) chia hết (4x+1)
2(1/4-3x)=1/5-4x
Tìm x 5/11-3x=2/3x-2;x-11/x-3=2/3;-4x-3/4=1-3x/3 giải giúp em nha
-4x (-1/2)^3-2x(-1/2)^2+3x(-1/2)+1
a, 3 - (7x - 6 ) - ( -4x + 2 ) = - ( -4 - 3x)
b, 4x + ( -8x + 3 ) = - (-7x +6 ) - 5 x
c, 6 - ( -4 -3x ) - ( 2 - 5x ) = 7 - ( 6x - 1 )
Tìm x biết:
3/4x-1/4=2(x-3)+1/4x
8/9x-2/3=1/3x+1 1/3
(x2 + 9) (9x2 -1) = 0
(4x2 -9) (2x-1 -1) =0
( 3x+2) (9-x2 ) =0
(3x+3)2 ( 4x - 42 ) =0
2(x-5) ( x+2) =1
Bài 1: Tìm x
a) | 2 + 3x | = | 4x - 3 |
b) | 7x + 1 | - | 4x - 3 |
