\(3^{x-1}+3^x+3^{x+1}-1=1052\)
\(3^x:3+3^x+3^x\cdot3=1053\)
\(3^x\left(\frac{1}{3}+1+3\right)=1053\)
\(3^x\cdot\frac{13}{3}=1053\)
\(3^x=243\)
\(x=5\)
\(3^{x-1}+3^x+3^{x+1}-1=1052\)
\(3^x:3+3^x+3^x\cdot3=1053\)
\(3^x\left(\frac{1}{3}+1+3\right)=1053\)
\(3^x\cdot\frac{13}{3}=1053\)
\(3^x=243\)
\(x=5\)
3x-1 +3x +3x+1 = 39
tìm x:
3x-1 + 3x + 3x+1 = 39
giúp mik với ;-;
1.Tìm x:
3x/2.5 + 3x/5.8 + 3x/8.11 +3x/11.14 =1/21
Tìm x, biết
a,(2x-1)luỹ thừa 3=23+102
b,(3x+1)+(3x+3)+(3x+5)+...+(3x+97)+(3x+99)=2800
Tìm x; biết: 3x + 3x+1 + 3x+2 + 3x+3 = 1080
3x/2.5 + 3x/2.8 + 3x/8.11 + 3x/11.14 = 1/21
Tìm x
a) -3 1/2 : (4/5-1/2x) = 2^2
b) 2x + 3x = 5
c) -2/3x - 1/3x = -2
d) -2/3 (x+1) - 1/2 = -1/3
3x + 3x+1 + 3x+2 = 117
Giúp mình con tính này với:
3x-1 + 3x + 3x+1 = 39 Bài tìm x nha
3x+1- 3x-1 =72