Question

( 3x-1).(2x-3).(x+5)= 0

Answer 1

(3x - 1)(2x - 3)(x + 5) = 0

⇔ 3x - 1 = 0 hoặc 2x - 3 = 0 hoặc x + 5 = 0

*) 3x - 1 = 0

⇔ 3x = 1

⇔ x = 1/3

*) 2x - 3 = 0

⇔ 2x = 3

⇔ x = 3/2

*) x + 5 = 0

⇔ x = -5

Vậy S = {-5; 1/3; 3/2}

Answer 2

(3x - 1)(2x - 3)(x + 5) = 0

\(\Leftrightarrow\left[{}\begin{matrix}3x-1=0\\2x-3=0\\x+5=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=\dfrac{3}{2}\\x=-5\end{matrix}\right.\) 

S = \(\left\{\dfrac{1}{3},\dfrac{3}{2},-5\right\}\)