(3x – 1)2 – (2 – x)2 = 5x -3
=>9x2-3x-1-(4-2x-x2)=5x-3
=>9x2-3x-1-4+2x+x2=5x-3
=>10x2-x-5-5x+3=0
=>10x2-6x+2=0
=>10x2-5x-x+2=0
=>5x(2x-1)?? =)
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\(\Leftrightarrow3x^2-2.3x.1+1^2-\left(4-4x+x^2\right)=5x-3\\ \Leftrightarrow9x^2-6x+1-4+4x-x^2=5x-3\\ \Leftrightarrow8x^2-2x-3=5x-3\\ \Leftrightarrow8x^2-2x-3-5x+3=0\\ \Leftrightarrow8x^2-7x=0\\ \Leftrightarrow x\left(8x-7\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\8x-7=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{7}{8}\end{matrix}\right.\)
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