Question

 \(3.\left(x+1\right)^3-27\left(x+1\right)=0\)

Answer 1

Đề bài là j z bn

Answer 2

tfim x

Answer 3

3.(x+1)³-27(x+1)=0

=>(x+1)[3.(x+1)²-27]=0

=>\(\hept{\begin{cases}x+1=0\\3.\left(x+1\right)-27=0\end{cases}}\)

Đến đây bạn tự làm nha,...

Answer 4

3(x+1)³ - 27(x+1) = 0

<=> 3(x+1)[(x+1)² - 9]=0

<=> 3(x+1)(x+1-3)(x+1+3)=0

<=>3(x+1)(x-2)(x+4)=0

=> x = {-1;2;-4}

Answer 5

\(3\left(x+1\right)^3-27\left(x+1\right)=0\)

\(\Rightarrow3\left(x+1\right)^3-3^3\left(x+1\right)=0\)

\(\Rightarrow3.\left(x+1\right)^2.\left(x+1\right)-3^3.\left(x+1\right)=0\)

\(\Rightarrow\left(x+1\right).\left(3.\left(x+1\right)^2-3^3\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+1=0\\3.\left(x+1\right)^2-3^3=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0-1\\3.\left(x+1\right)^2=3^3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-1\\\left(x+1\right)^2=3^3:3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-1\\\left(x+1\right)^2=3^2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-1\\x+1=\pm3\end{cases}}\)

\(\Rightarrow x=-1;\orbr{\begin{cases}x+1=3\\x+1=-3\end{cases}}\)

\(\Rightarrow x=-1;\orbr{\begin{cases}x=3-1\\x=-3-1\end{cases}}\)

\(\Rightarrow x=-1;\orbr{\begin{cases}x=2\\x=-4\end{cases}}\)

Vậy x = -1 hoặc x = 2 hoặc x = - 4