\(3\frac{1}{5}x+125x=178\)
=> 3,2x + 125x = 178
=> 128,2x = 178
\(\Rightarrow x=\frac{890}{641}\)
\(3\frac{1}{5}x+125x=178 \)
\(\frac{16}{5}x+125x=178\)
\(x.\left(\frac{16}{5}+125\right)=178\)
\(x.\frac{641}{5}=178\)
\(x=178:\frac{641}{5}\)
\(x=\frac{890}{641}\)
vậy \(x=\frac{890}{641}\)
Tìm X, biết:
\(\frac{16}{5}x=178-125x\)
125x(-61)x(-2)3x(-1)2nx(n thuộc n*
Hãy so sánh:
a) A= \(\frac{178}{179}+\frac{179}{180}+\frac{183}{181}\)với 3.
b) A= \(\frac{1+5+5^2+5^3+...+5^{10}+5^{11}}{1+5+5^2+5^3+...+5^9+5^{10}}\)và B=\(\frac{1+7+7^2+7^3+...+7^{10}+7^{11}}{1+7+7^2+7^3+...+7^9+7^{10}}\)
(1- \(\frac{1}{3}\)) x(1-\(\frac{1}{6}\)) x(1- \(\frac{1}{10}\))x (1-\(\frac{1}{15}\))...(1-\(\frac{1}{178}\)) x a=1
Thực hiện phép tính;
a) 25x(32+47)-32x(25+47)
b) (-11)9:[5x(-11)5-16x(-11)5]
c)125x(-61)x(-2)3x(-1)2n (n thuộc N*)
B= 1037 + { 743 - [ 1031 - (+57) ] }
C= ( 125x 73 - 125 x 75): ( -25 x 2)
D= - 25 x ( 35 + 147)+ 35 x ( 25 + 147)
E= 125 x 9x (-4)x (-8) x 25 x 7
G= ( -3)2 + ( - 5)3 : /-5/
Tìm x:
a) 541 + ( 218 - x ) = 735
b) 96 - 3 ( x + 1 ) + 42
c) [ 178 - ( 13x - 8 ) . 53 + 5724
d) ( x - 5 ) . ( x - 7 ) = 0
Áp dụng quy tắc chuyển vế
a)2x+5=(-10)-x
b)5^2+125x=0
c)7x^2-21x+5=5
so sánh \(\frac{178}{179}+\frac{179}{180}+\frac{183}{181}\)với 3
