\(a,=\dfrac{3}{8}-\left(\dfrac{6}{5}-\dfrac{5}{8}\right)\\ =\dfrac{3}{8}-\dfrac{6}{5}+\dfrac{5}{8}\\ =1-\dfrac{6}{5}\\ =\dfrac{5-6}{5}\\ =-\dfrac{1}{5}\\ b,=\dfrac{52}{5}-\dfrac{15}{4}-\dfrac{25}{4}\\ =\dfrac{52}{5}-\dfrac{40}{4}\\\\ =\dfrac{52}{5}-\dfrac{10}{1}\\ =\dfrac{52-50}{5}\\ =\dfrac{2}{5}\\ c,=-\dfrac{9}{7}+\left(-1,23-0,77\right)+\dfrac{2}{7}\\ =-\dfrac{7}{7}-2\\ =-1-2=-3 \)