Question

`37/43 . 17/29 - 29/41 . 1/2 + 9/58 : 1 6/37 - 6/29 : 1 20/21`

`(8 + 2 1/3 - 3/5) - (5+0,4) - (3 1/3 -2)`

`(2/9 - 7/12) : 3/4 + (16/9 - 5/12) : 3/4`

`-4/12 - (-13/39 - 0,25) + 0,75`

`2/5 - (4/3 + 4/5) - (-1/9 - 0,4) + 11/9`

Answer 1

 

\(\left(8+2\dfrac{1}{3}-\dfrac{3}{5}\right)-\left(5+0,4\right)-\left(3\dfrac{1}{3}-2\right)\)

\(=8+2+\dfrac{1}{3}-\dfrac{3}{5}-5-\dfrac{2}{5}-3-\dfrac{1}{3}+2\)

\(=12-5-1=6\)

\(\left(\dfrac{2}{9}-\dfrac{7}{12}\right):\dfrac{3}{4}+\left(\dfrac{16}{9}-\dfrac{5}{12}\right):\dfrac{3}{4}\)

\(=\left(\dfrac{2}{9}-\dfrac{7}{12}+\dfrac{16}{9}-\dfrac{5}{12}\right):\dfrac{3}{4}\)

\(=\left(2-1\right):\dfrac{3}{4}=1\cdot\dfrac{4}{3}=\dfrac{4}{3}\)

\(-\dfrac{4}{12}-\left(-\dfrac{13}{39}-0,25\right)+0,75\)

\(=-\dfrac{1}{3}+\dfrac{1}{3}+0,25+0,75\)

=0,25+0,75=1

\(\dfrac{2}{5}-\left(\dfrac{4}{3}+\dfrac{4}{5}\right)-\left(-\dfrac{1}{9}-0,4\right)+\dfrac{11}{9}\)

\(=\dfrac{2}{5}-\dfrac{4}{3}-\dfrac{4}{5}+\dfrac{1}{9}+\dfrac{2}{5}+\dfrac{11}{9}\)

\(=\dfrac{2}{5}+\dfrac{2}{5}-\dfrac{4}{5}+\left(-\dfrac{4}{3}+\dfrac{1}{9}+\dfrac{11}{9}\right)\)

\(=0+\left(-\dfrac{4}{3}+\dfrac{12}{9}\right)=0\)