a: Ta có: \(36\le6^x\le1296\)
\(\Leftrightarrow2\le x\le4\)
hay \(x\in\left\{2;3;4\right\}\)
b: Ta có: \(100< 5^{2x-1}< 5^6\)
\(\Leftrightarrow2x-1\in\left\{3;5\right\}\)
\(\Leftrightarrow2x\in\left\{4;6\right\}\)
hay \(x\in\left\{2;3\right\}\)
a: Ta có: \(36\le6^x\le1296\)
\(\Leftrightarrow2\le x\le4\)
hay \(x\in\left\{2;3;4\right\}\)
b: Ta có: \(100< 5^{2x-1}< 5^6\)
\(\Leftrightarrow2x-1\in\left\{3;5\right\}\)
\(\Leftrightarrow2x\in\left\{4;6\right\}\)
hay \(x\in\left\{2;3\right\}\)
1) (x + 1/2).(2/3 - 2x) = 0 2) 2/3x + 1/2x = 5/2 : 3 và 3/4 3) (2x - 3)(6 - 2x)= 0 4) -5(x + 1/5) - 1/2(x - 2/3) = 3/2x - 5/6
1,Tìm x
5^x-5^x+2=650
2x-3/11+2x-4/12+2x-5/13=2x-6/14+2x-7/15+2x-8/6
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
1,x=3x2
2,(x+5)(x-3)-(x-30)=0
3,(2x-6)(x+4)+2(2x-6)=0
4,(2x-5)(x+9)+6x-15=0
3,(2x-5)(x+6)+8x-20=0
Tìm x biết:
a,x-5/7=1/9
b,2x/5=6/2x+1
c,11/8+13/6=85/x
d,2x-2/11=1.1/5
e,x/15=3/5+-2/3
f,x/182=-6/14.35/91
1. | 4-2x | . 1/3 = 1/3
2. (-3)² : | x+(-1) | = (-3)
3. | 3/2 -x | + (-4/5) = -14/5
4. (-4/3) - | 2x + (-1) | = -7/3
5. -9 . | 36 - x/2 | = (-54)
6. 0,75 - | (-x) + 1/3 | = 0,25
7. (-6/5) + | x-9 |= (-6/5)
8. (-4) . | 3x - 1/5 | = 12
a,x - 1/2 - (-1/6)
b,x + 5/6 = 3/8
c,2/3 . x -1/2 = 5/6
d, x/7 = 6/-21
e,(7/3 x -0,6) : 3^2/5 = 1
f,x/45 = 5/6 + -29/30
g,(4,5 - 2x) . (-1^4/7) =11/14
h,-2/7 + 4/7x=5/7
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
Giải thích hộ :v