\(\frac{35}{41}.\left(-\frac{25}{21}\right).\left(-\frac{82}{15}\right)-\left|5\frac{1}{3}-0,35\right|\)
= \(\frac{35.\left(-25\right).\left(-82\right)}{41.21.15}-\frac{299}{60}\)
= \(\frac{50}{9}-\frac{299}{60}\)
= \(\frac{1000-897}{180}\)= \(\frac{103}{180}\)
\(\frac{35}{41}.-\frac{25}{21}.-\frac{82}{15}-|\frac{51}{3}-0,35|\)
\(=\frac{71750}{12915}-|\frac{51}{3}-\frac{35}{100}|\)
\(=\frac{71750}{12915}-|\frac{5100}{300}-\frac{105}{300}|\)
\(=\frac{71750}{12915}-\frac{4995}{300}\)
\(=...\)
Tự quy đồng rồi rút gọn nhé !!!
\(\frac{35}{41}.\left(-\frac{25}{21}\right).\left(-\frac{82}{15}\right)-\left|5\frac{1}{3}-0,35\right|\)
\(=\frac{35.25.82}{41.21.15}-\left|\frac{16}{3}-\frac{35}{100}\right|\)
\(=\frac{5.7.5.5.41.2}{41.7.3.5.3}-\left|\frac{16}{3}-\frac{7}{20}\right|\)
\(=\frac{5.7.5.5.41.2}{41.7.3.5.3}-\left(\frac{16}{3}-\frac{7}{20}\right)\)
\(=\frac{50}{9}-\frac{16}{3}+\frac{7}{20}\)
\(=\frac{2}{9}+\frac{7}{20}=\frac{103}{180}\)
Toán này là toán lớp 7 mà ?
