\(\dfrac{3}{2}\)x\(\dfrac{4}{3}\)x\(\dfrac{5}{4}\)x...x\(\dfrac{2022}{2023}\)
⇒
⇒\(\dfrac{2022}{2}\)=1011
Lời giải:
$\frac{3}{2}\times \frac{4}{3}\times \frac{5}{4}\times .... \times \frac{2022}{2021}$
$=\frac{3\times 4\times 5\times ....\times 2022}{2\times 3\times 4\times ...\times 2021}=\frac{2022}{2}=1011$