\(3^{2x-1}=27\)
\(3^{2x-1}=3^3\)
\(2x-1=3\)
\(2x=3+1=4\)
\(x=\dfrac{4}{2}=2\)
3^2x-1=27
2x-1=27:3
2.x-1=9
2.x=9-1
2.x=8
x=8:2
x=4
vậy x =4
mong cho 1 vote và 5 sao
32x-1=27
32x-1=33
2x-1=3
2x=3+1
2x=4
x=4:2
x=2
Vậy x = 2
\(3^{2x-1}\)=27
\(\Rightarrow\)\(3^{2x}:3^1\)=27
\(3^{2x}\)=27:3
\(3^{2x}\)=9
\(\Rightarrow3^{2x}\)=\(3^2\)
\(\Rightarrow3^2.3^x\)=\(3^2\)
\(3^x\)=1