\(\left(\dfrac{3}{2}\right)^7:\left(\dfrac{7}{2}\right)^5+\dfrac{3}{2}\)
\(=\dfrac{3^7}{2^7}\cdot\dfrac{2^5}{7^5}+\dfrac{3}{2}\)
\(=\dfrac{3^7}{7^5\cdot2^2}+\dfrac{3}{2}\)
\(=\dfrac{3^7+3\cdot7^5\cdot2}{2^2\cdot7^5}\)
\(=\dfrac{103029}{67228}\)
\(\left(\dfrac{3}{2}\right)^7:\left(\dfrac{7}{2}\right)^5+\dfrac{3}{2}\)
\(=\dfrac{3^7}{2^7}\cdot\dfrac{2^5}{7^5}+\dfrac{3}{2}\)
\(=\dfrac{3^7}{7^5\cdot2^2}+\dfrac{3}{2}\)
\(=\dfrac{3^7+3\cdot7^5\cdot2}{2^2\cdot7^5}\)
\(=\dfrac{103029}{67228}\)
(3-1/4+2/3) - (5-1/3-6/5) - (6-7/4+3/2) (6-2/3+1/2) - (5+5/3-3/2)-(3-7/3+5/2)
(5/3-3/7+9)-(2+5/7-2/3)+(8/7-4/3-10) (8-9/4+2/7)-(-6-3/7+5/4)-(3+2/4-9/7 )
mọi người ơi giúp mik với ạ
5) (3-1/4+2/3) - (5-1/3-6/5) - (6-7/4+3/2) 6) (6-2/3+1/2) - (5+5/3-3/2)-(3-7/3+5/2)
7) (5/3-3/7+9)-(2+5/7-2/3)+(8/7-4/3-10) 8) (8-9/4+2/7)-(-6-3/7+5/4)-(3+2/4-9/7 pls help me
1, ( -2/5 + 3/10 ) : ( 2/-5 + |-4/3 - 2| )
2, 12,5 . -5/7 + 9 3/4 - 1,5 . 5/7
3, -1/4 . -5/13 - 5/4 . -7/13 + 1/1,3
4, ( -3/4 + 5/13 ) : 2/7 - ( 2 1/4 + 8/13 ) : 2/7
5, ( 3 - 3/4 + 2/3 ) - ( 2 - 4/3 - 3/2 ) - ( 1 - 7/3 - 9/2 )
6, -1/3 - 8/35 + -2/9 - 1/135 z+ 4/5 + -4/9 + 3/7
a)-1/24-[1/4-(1/2-7/8)]
b)(5/7-7/5)-[-1/2-(-2/7-1/10)
c)(-1/2)-(-3/5)+(-1/9)+1/71-(-2/7)+4/35-7/18
d) (3-1/4+2/3) -(5-1/3-6/5)-(6-7/4+3/2)
2\(^7\) + ( x - 3\(^7\) ) = 5\(^7\) - 4\(^7\)
3 \(^x\) - (x + 2 \(^x\)) = 7
7 \(^2\) - (15 + x) = 5.2 \(^2\)
7 \(^3\) - 7(13 - x) = 14
Rút gọn: (6 ^ 6 + 2 ^ 7 * 3 ^ 6 + 2 ^ 6 * 3 ^ 7)/(4.2 ^ 3 * 3 ^ 2 * 2 ^ 2)
Tính:
a) (1/7)^7 .7^7
b) (0,125)^3 .512
c) (0,25)^4 .1024
d) 90^3/15^3
e) 3^2/0,375^2
f) 3^2 .1/234 .81^2 .1/3^3
g) (4.2^5) : (2^3 .1/16)
h) (2^-1 + 3^-1) : (2^-1 - 3^-1) + (2^-1 .2^0) : 2^3
i) (-1/3)^-1 - (-6/7)^9 + (1/2)^2 : 2
Cách giải chi tiết.
(1/5-2/7).3/4-3/4.(1/3-2/7)/1/5.2/7-1/3.(2/7+3/9)+3/9.1/5
Bài 1:
a) (6-2/3+1/2)-(5+5/3-2/3)-(3-7/3+5/2)
b)(-1/1/2:1,25)+(10/3/7:5/3/14)
c)(-2/3+1/7):121/42
b)2/7-3/7:(-3/2) c)(3/7-3,5)-(3/7-7/2) d)0,25.34/29+-5/29.(-1/2)mủ 2 làm ra hộ mình với nha cả cách trình bày với ạ