\(\dfrac{3}{8}\times\dfrac{2}{3}+\dfrac{1}{4}=\dfrac{6}{24}+\dfrac{1}{4}=\dfrac{6}{24}+\dfrac{6}{24}=\dfrac{12}{24}=\dfrac{1}{2}\)
\(\dfrac{1}{3}:\dfrac{2}{9}-\dfrac{5}{6}=\dfrac{1}{3}\times\dfrac{9}{2}-\dfrac{5}{6}=\dfrac{9}{6}-\dfrac{5}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
#YTVA