\(3-\dfrac{7}{13}+\dfrac{5}{11}+\dfrac{33}{13}-1+\dfrac{6}{11}\\ =\left(3-1\right)+\left(\dfrac{-7}{13}+\dfrac{33}{13}\right)+\left(\dfrac{5}{11}+\dfrac{6}{11}\right)\\ =2+\dfrac{33-7}{13}+\dfrac{5+6}{11}\\ =2+\dfrac{26}{13}+\dfrac{11}{11}\\ =2+2+1\\ =5\)