\(\dfrac{3}{1.4}+\dfrac{3}{4.7}+...+\dfrac{3}{100.103}\)
\(=1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{100}-\dfrac{1}{103}\)
\(=1-\dfrac{1}{103}\)
\(=\dfrac{103}{103}-\dfrac{1}{103}\)
\(=\dfrac{102}{103}\)
Đúng 0
Bình luận (0)