Question

3 + 2 / \{1 + 3 / [2 - 1 / (3 + 2/(1 - 3))]}

giúp mình vs,đg cần gấp

Answer 1

$=3+2\text{/}\left{1+3\text{/}\left[2-1\text{/}\left(3+2\text{/}\left(1-3\right)\right)\right]\right}$
$=3+2\text{/}\left{1+3\text{/}\left[2-1\text{/}\left(3+2\text{/}\left(-2\right)\right)\right]\right}$
$=3+2\text{/}\left{1+3\text{/}\left[2-1\text{/}\left(3+\left(-1\right)\right)\right]\right}$
$=3+2\text{/}\left{1+3\text{/}\left[2-1\text{/}2\right]\right}$
$=3+2\text{/}\left{1+3\text{/}\left[2-0.5\right]\right}$
$=3+2\text{/}\left{1+3\text{/}1.5\right}$
$=3+2\text{/}\left{1+2\right}$
$=3+2\text{/}3$

\(=\dfrac{3\cdot3+2}{3}\)

\(=\dfrac{11}{3}\)

Answer 2

$3+2/{1+3/[2-1/(3+2/(1-3))]}$
$3+2/{1+3/[2-1/(3+2/(-2))]}$
$3+2/{1+3/[2-1/(3+(-1))]}$
$3+2/{1+3/[2-1/2]}$
$3+2/{1+3/[2-0.5]}$
$3+2/{1+3/1.5}$
$3+2/{1+2}$
$3+2/3$
\(=\dfrac{3\cdot3+2}{3}\)

\(=\dfrac{11}{3}\)