\(\left(2x+\dfrac{5}{3}\right).\left(\dfrac{5}{4}-x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x+\dfrac{5}{3}=0\\\dfrac{5}{4}-x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=\dfrac{-5}{3}\\x=\dfrac{5}{4}-0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{-5}{3}:2\\x=\dfrac{5}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{-5}{6}\\x=\dfrac{5}{4}\end{matrix}\right.\)
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