`2x^3 - 6 =10`
`=> 2x^3 = 6+10`
`=> 2x^3 = 16`
`=> x^3 = 16:2`
`=>x^3 =8`
`=> x^3 = 2^3`
`=> x=2`
Vậy `x=2`
\(2x^3-6=10\\ \Leftrightarrow2x^3=16\\ \Leftrightarrow x^3=8\\ x=2\)
`2x^3 - 6 =10`
`=> 2x^3 = 6+10`
`=> 2x^3 = 16`
`=> x^3 = 16:2`
`=>x^3 =8`
`=> x^3 = 2^3`
`=> x=2`
Vậy `x=2`
\(2x^3-6=10\\ \Leftrightarrow2x^3=16\\ \Leftrightarrow x^3=8\\ x=2\)
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
tìm số nguyên x biết
a) -x/2+ 2x/3 + x+1/4 + 2x+1/6 = 3/8
b) 3/2x+1 + 10/4x+2 - 6/6x+3 = 12/26
(21-3x).(2x-10).(6-2x=0
2011(2x-6.(21-3x))=1
33x+2 + 5.32x. 23+234= 4203
Tìm x thuộc N,biết:
1) 42x-6 =1
2) (3x-9)7 = 0
3) (3-x)10x : (3-x)20 =1 (với x khác 3)
4) (x-6)3 = (x-6)2
5) { [ (2x+14):22 -3 ]:2 } -1 = 0
6) 10- {[(x:3+17) : 10 + 3.24 ]:10 } = 5
7) x10 = 1x
8) x10 = x
9) (2x - 15)5 = (2x - 15)3
10) ( 7x -11 )3 = 25.52 + 200
2x^3 -3^4 = 5^6 . -12^10
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
Giải thích hộ :v
tìm số nguyên x
5/x+1+4/x+1=3/-13
-x+2+2x+3+x+1/4+2x+1/6=8/3
3/2x+1+10/4x+2-6/6x+2=12/26
giúp mình mik đang vội]
bài 2: viết thành dạng lũy thừa các tích sau:
a) 2 . 2 . 2 . 2 . 2 . 2 . 2 . 2
b) 10 . 10 . 10 . 10 . 10
c) 8 . 8 . 8 . 6 . 6 . 6 . 7 . 7 . 7
d) a . a . a . a . a . a . a . a . a
e) 10000 . 10 . 10 . 10 . 100
f) 2x . 2x . 2x . 2x . 2x
nhanh nha, mik tick cho