Các câu hỏi tương tự
Tìm x,biết:\(2^x+2^{x+1}+2^{x+2}+2^{x+3}+...+2^{x+2021}=2^{2025}+8\)
Tìm số nguyên dương x sao cho 5x +13 là bội của 2x+1
Tìm x biết (2x-18).(3x+12)=0
Tính S= 1-2-3+4+
5-6-7+8+...+2021-2022-2023+2024+2025
tìm số nguyên x,y
a\(y^2\)=3-|2x-3|
b2.\(y^2\)=3-|x+4|
c25-\(y^2\)=8.\(\left(x-2021\right)^2\)
tìm x biết A=(1+2/3).x.(1+2/5).x.(1+2/7).x...x(1+2/2021)
3.1
a) 41 - 2x+1= 9
b)52021.5x-3=52022
c) 102021.( x + 5 ) = 102022
d)52x-3- 2.52 = 52.3
e)2x+1 - 2x = 32
f) 32x-4 - x0=8
g)65 - 4x+2=20210
Tìm x,biết :
1: (x+8)2=7225
2: x2-190=710
3: (2x-1)2-1000=0
4: 2x+1 . 162=1287
5: x20-x10=0
6:(x-1)10-(x-1)5=0
7:2x+2x+4=272
8: (2x+1)2=2025
9: (7x-11)3=25 . 52+200
Cần gấp ! ai nhanh tick
*Thực hiện1/ (dfrac{2021}{2020}+dfrac{2020}{2021}) x (dfrac{1}{2}-dfrac{1}{3}-dfrac{1}{6})2/ (dfrac{7}{19}-dfrac{5}{12}):dfrac{-5}{8}-(dfrac{7}{19}-dfrac{29}{12}):dfrac{5}{8}3/ dfrac{-5}{6}xdfrac{7}{24}-dfrac{5}{6}xdfrac{14}{24}-dfrac{5}{6}xdfrac{3}{24}
Đọc tiếp
*Thực hiện
1/ (\(\dfrac{2021}{2020}\)+\(\dfrac{2020}{2021}\)) x (\(\dfrac{1}{2}\)-\(\dfrac{1}{3}\)-\(\dfrac{1}{6}\))
2/ (\(\dfrac{7}{19}\)-\(\dfrac{5}{12}\)):\(\dfrac{-5}{8}\)-(\(\dfrac{7}{19}\)-\(\dfrac{29}{12}\)):\(\dfrac{5}{8}\)
3/ \(\dfrac{-5}{6}\)x\(\dfrac{7}{24}\)-\(\dfrac{5}{6}\)x\(\dfrac{14}{24}\)-\(\dfrac{5}{6}\)x\(\dfrac{3}{24}\)
Cho x1 + x2 + x3 + ... + x2021 = 0 và x1 + x2 = x3 + x4 = ... = x2019 + x2020 = 2. Tìm x2021.
bai 5 : tinh
a) tim x , biet (x+1) +(x+2 ) + ...+(x+100)=5750
b) chung minh rang B = 1/2^2 + 1/3^2 + 1/4^2 + ...+1/2021^2 < 1
giup mik luon voi