\(2x^2-x.\left(x-2\right)-3=0\)
\(2x^2-x^2+2x-3=0\)
\(x^2+2x-3=0\)
\(\left(x^2-x\right)+\left(3x-3\right)=0\)
\(x.\left(x-1\right)+3.\left(x-1\right)=0\)
\(\left(x-1\right)\left(x+3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\x+3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=1\\x=-3\end{cases}}}\)
Vậy \(\orbr{\begin{cases}x=1\\x=-3\end{cases}}\)
2x2 - x.( x - 2 ) - 3 = 0
\(\Leftrightarrow2x^2-x^2+2x-3=0\)
\(\Leftrightarrow x^2+2x-3=0\)
\(\Leftrightarrow x^2-x+3x-3=0\)
\(\Leftrightarrow x\left(x-1\right)+3\left(x-1\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(x-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+3=0\\x-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-3\\x=1\end{cases}}\)
Vậy....
