\(2x+\dfrac{1}{7}=x+\dfrac{5}{5}\)
\(⇔2x-x=1-\dfrac{1}{7}\)
\(⇔x=\dfrac{6}{7}\)
Đúng 1
Bình luận (0)
Các câu hỏi tương tự
\(\dfrac{7^{x+2}+7^{x+1}+7^x}{57}=\dfrac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
14 tháng 11 2023 lúc 18:37
a,|7 - 2x| + 7 = 2x
b,| 1 - x | = 4x + 1
c, | x - 1/3 | + 4/5 = | ( 3,2) + 2/5 |
d,| x - 7 | + 2x + 5 = 6
e, 3x - | 2x - 1 | = 2
Tìm x:
\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
Tìm x \(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
tìm x biết : \(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
Tìm x
\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
ho minh nha
\(\frac{7^{x+1}+7^{x+2}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
Tìm x biết \(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
Tìm x biết \(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
(7(x+2)+7(x+1)+7x )/57= [5(2x)+5(2x+1)+5(2x+3) ]/131