\(2\left(x-\frac{1}{2}\right)+3\left(-1+\frac{x}{3}\right)=x\left(\frac{2}{x}-1\right)\)
\(\Leftrightarrow2x-1-3+\frac{3x}{3}=\frac{2x}{x}-x\)
\(\Leftrightarrow2x-1-3+x=x-x\)
\(\Leftrightarrow2x-4+x=0\)
\(\Leftrightarrow3x-4=0\)
\(\Leftrightarrow3x=0+4\)
\(\Leftrightarrow3x=4\)
\(\Leftrightarrow x=\frac{4}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
tìm x :
a)\(x:4\frac{1}{3}=2.5\)
b)\(x:\frac{-3}{5}=\frac{-10}{21}\)
c)\(\frac{2}{3}.x-\frac{1}{2}=\frac{1}{10}\)
d)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)
e)\(\frac{1}{2}.x+\frac{1}{2}=\frac{5}{2}\)
f)\(\frac{-2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)
g)\(\left(3x-1\right)\left(-\frac{1}{2}.x+5\right)=0\)
h)\(3\frac{1}{3}+\frac{5}{6}.x=3\frac{1}{2}\)
Tìm x
\(\left(2x+\frac{3}{5}\right)^2-\frac{9}{25}=0\)
\(3\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
giải nhanh hộ mình với, mai mình nộp rồi
tìm x :
\(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)
\(3\left(x-\frac{1}{2}\right)-5\left(x-\frac{2}{3}\right)=\frac{3}{2}x\)
tìm x
a) \(\frac{x-1}{2}+\frac{x-2}{5}=\frac{1}{4}+\frac{x-7}{10}\)
b) \(3-\frac{2}{2x-3}=\frac{2}{5}+\frac{1}{2x-3}-\frac{3}{2}\)
c)\(7\cdot\left(x-1\right)+2x\cdot\left(1-x\right)=0\)
d) \(\frac{x+1}{2008}+\frac{x+2}{2017}+\frac{x+3}{2016}=\frac{x+10}{2009}+\frac{x+11}{2008}+\frac{x+12}{2007}\)
e) \(\frac{2}{\left(x-1\right)\cdot\left(x-3\right)}+\frac{5}{\left(x-3\right)\cdot\left(x-8\right)}+\frac{12}{\left(x-8\right)\cdot\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
Tìm x, biết:
a)\(\frac{x}{5}\)= \(\frac{2}{3}\)
b)\(\frac{x}{-24}\) = \(\frac{20}{40}\)
c)\(\frac{x+3}{15}\) = \(\frac{1}{3}\)
d)\(\frac{2}{3}.x-\frac{3}{2}.x=\frac{5}{12}\)
e)\(\frac{-2}{3}.x+\frac{1}{5}.x-\frac{3}{10}=0\)
f)\(\frac{-2}{3}-\frac{1}{3}.\left(2.x-5\right)=\frac{3}{2}\)
g)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)
Tìm x biết
\(\frac{1}{3}x+650\%x-x=-6\)
\(2\left(x-\frac{1}{2}\right)+3\left(-1+\frac{x}{3}\right)=x\left(\frac{2}{x}-1\right)\)
\(\frac{x-2}{20}=\frac{5}{2-x}\)
\(\left(\frac{x}{3}+\frac{1}{2}\right)\left(75\%-1\frac{1}{2}\right)=0\)
Bài tập: Tìm x, biết:
a) \(\frac{3}{5}-\frac{4}{3}-x=\frac{-1}{2}\)
b) \(\frac{1}{2}x+\frac{1}{3}x+\frac{1}{6}x=\frac{2}{9}\)
c) \(\left(\frac{1}{3}x+\frac{3}{2}\right)\cdot\left(\frac{3}{2}x-\frac{4}{3}\right)=0\)
( Cần gấp nhé. Mong các bạn giúp mình. )
a)\(\frac{1}{6}x+\frac{1}{10}-\frac{4}{15}x+1=\)\(0\)
b)\(\left(\frac{1}{7}x-\frac{2}{7}\right).\left(-\frac{1}{5}x+\frac{3}{5}\right).\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
c)\(\frac{1}{2}x-\frac{11}{15}:\frac{33}{35}=-\frac{1}{3}\)
Tìm x biết:
