\(2x=3y=4z\Rightarrow\dfrac{2x}{12}=\dfrac{3y}{12}=\dfrac{4z}{12}\Rightarrow\dfrac{x}{6}=\dfrac{y}{4}=\dfrac{z}{3}\)
Áp dụng t/c dtsbn:
\(\dfrac{x}{6}=\dfrac{y}{4}=\dfrac{z}{3}=\dfrac{x-y+z}{6-4+3}=\dfrac{35}{5}=7\\ \Rightarrow\left\{{}\begin{matrix}x=42\\y=28\\z=21\end{matrix}\right.\)
\(2x=3y=4z\Rightarrow\dfrac{x}{6}=\dfrac{y}{4}=\dfrac{z}{3}\)
Áp dụng t/c dtsbn:
\(\dfrac{x}{6}=\dfrac{y}{4}=\dfrac{z}{3}=\dfrac{x-y+z}{6-4+3}=\dfrac{35}{5}=7\)
\(\Rightarrow\left\{{}\begin{matrix}x=7.6=42\\y=7.4=28\\z=7.3=21\end{matrix}\right.\)