Question

(2x-3).(2x+5)=0

Answer 1

Ta có:

(2x - 3)(2x + 5) = 0

=> \(\left[\begin{matrix}2x-3=0\\2x+5=0\end{matrix}\right.\)

=> \(\left[\begin{matrix}2x=3\\2x=-5\end{matrix}\right.\)

=> \(\left[\begin{matrix}x=\frac{3}{2}\\x=\frac{-5}{2}\end{matrix}\right.\)

Vậy x = \(\frac{3}{2}\) hoặc x = \(\frac{-5}{2}\).

Answer 2

(2x - 3) . (2x + 5) = 0

=> 2x - 3 = 0 hoặc 2x + 5 = 0

+) 2x - 3 = 0

=> 2x = 0 + 3 = 3

=> x = \(\frac{3}{2}\)

+) 2x + 5 = 0

=> 2x = -5

=> x = \(\frac{-5}{2}\)

Vậy...............

Answer 3

(2x-3)(2x+5)=0

\(\Rightarrow\left[\begin{matrix}2x-3=0\\2x+5=0\end{matrix}\right.\)

\(\Rightarrow\left[\begin{matrix}x=\frac{3}{2}\\x=\frac{-5}{2}\end{matrix}\right.\)

vậy ......