Ta có:
(2x - 3)(2x + 5) = 0
=> \(\left[\begin{matrix}2x-3=0\\2x+5=0\end{matrix}\right.\)
=> \(\left[\begin{matrix}2x=3\\2x=-5\end{matrix}\right.\)
=> \(\left[\begin{matrix}x=\frac{3}{2}\\x=\frac{-5}{2}\end{matrix}\right.\)
Vậy x = \(\frac{3}{2}\) hoặc x = \(\frac{-5}{2}\).
(2x - 3) . (2x + 5) = 0
=> 2x - 3 = 0 hoặc 2x + 5 = 0
+) 2x - 3 = 0
=> 2x = 0 + 3 = 3
=> x = \(\frac{3}{2}\)
+) 2x + 5 = 0
=> 2x = -5
=> x = \(\frac{-5}{2}\)
Vậy...............
(2x-3)(2x+5)=0
\(\Rightarrow\left[\begin{matrix}2x-3=0\\2x+5=0\end{matrix}\right.\)
\(\Rightarrow\left[\begin{matrix}x=\frac{3}{2}\\x=\frac{-5}{2}\end{matrix}\right.\)
vậy ......