2x-1/3=-5/6
2x=-5/6+1/3
2x=-1/2
x=-1/2:2
x=-1/4
Vậy ...
\(2x-\dfrac{1}{3}=\dfrac{-5}{6}\)
\(2x=\dfrac{-5}{6}+\dfrac{1}{3}\)
\(2x=-\dfrac{1}{2}\)
\(x=-\dfrac{1}{2}:2\)
\(x=-\dfrac{1}{4}\)
Học tốt :)
Tìm x biết : a) 2x+3/15 = 7/5. b) x-2/9 = 8/3. c) -8/x = -x/18 d) 2x+3/6 = x-2/5. e) x+1/22 = 6/x f) 2x-1/2 = 5/x g) 2x-1/21 = 3/2x+1 h) 10x+5/6 = 5/x+1
Bài 2 Tìm x biết 1, (2x-2).(3x+1)-(3x-2).(2x-3)=5 2,(1-3x).(3x-5)-(2x-4)(2-3x)=x-6 3,(2x-1).(4x^2+2x+1)-(2x+1)(4x^2-2x+1)=5x+6 Giúp tớ với
\(\dfrac{x-3}{3}=\dfrac{2x+1}{5}\)
\(\dfrac{x+1}{22}=\dfrac{6}{x}\)
\(\dfrac{2x-1}{2}=\dfrac{5}{x}\)
\(\dfrac{2x-1}{21}=\dfrac{3}{2x+1}\)
\(\dfrac{2x+1}{9}=\dfrac{5}{x+1}\)
Tìm x
tim x
a/ (5x -1)^6 =729
b/(2x+1)^3=0,001
c/(2x-3)^4=(2x-3)^6
d/(2x+1)^5=(2x+1)^2010
,Tìm x, biết:
a, 3|x+4| - |2x+1| = 5
b, |x+5| - 3|2x+5| = 8
c,3|2x-3| - 6|x-1| = 3
Bài 1: Tìm x; y ϵ \(ℤ\)
a) 2x - y\(\sqrt{6}\) = 5 + (x + 1)\(\sqrt{6}\)
b) 5x + y - (2x -1)\(\sqrt{7}\) = y\(\sqrt{7}\) + 2
Bài 2: So sánh M và N
M = \(\dfrac{\dfrac{3}{4}+\dfrac{3}{5}+\dfrac{3}{7}-\dfrac{3}{11}}{\dfrac{6}{4}+\dfrac{6}{5}+\dfrac{6}{7}-\dfrac{6}{11}}\)
N = \(\dfrac{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}{\dfrac{6}{2}+\dfrac{6}{5}-\dfrac{6}{7}-\dfrac{6}{11}}\)
Bài 3: Chứng minh:
\(\dfrac{1}{2!}+\dfrac{1}{3!}+\dfrac{1}{4!}+...+\dfrac{1}{2023!}< 1\)
Bài 1:
a.35 1/6:(-4)/5-46 1/6:(-4)/5
b.1/6+5/6.3/2-3/2+1
c.-1/12-(2 5/8-1/3)
d.-5/4.8/9+-7/16.8/9-2
e.1/6.(-2 3/5)+1 2/5.(-13/5)
Bài 2
a.-5/8+x=(-2/3)^2
b.-1/4-3/4:x=-11/36
c.-22/15x+1/3=/-2/3-1/5/
d./-1/2-x/=1/3
e./2x+3/4/-6=-5
f.-5/7-/1/2-x/=-11/4
g.//x+5/-4/=3
h./17x-5/=/17x+5/
i./x-1/=2x-5
k.(x-1)^3=27
l.(2x-1)^2=25
n.5^x+2=625
m.(2x-1)^3=-8
o.x^2+x=0
2x - 2/3 + 1/2x = -1
31/36 - (1/3 - x)2 = 5/6
Tìm x để biểu thức nhận giá trị âm
2, 2x . (x+1)
3, 5x - x^2
4, (x+3) . (1-2x)
5, (x - 2/5) (x + 3/7) (x +3/4)
6, (x + 3/5) (x - 2/3) (2x +1
\(x^2-19=5.9;\left(2x+1\right)^3=-0,001;\left(\dfrac{5}{6}\right)^{2x-1}=\left(\dfrac{5}{6}\right)^5;\left(\dfrac{1}{3}x-\dfrac{2}{3}\right)^3=27;\left(\dfrac{1}{32}\right)^x=\left(\dfrac{1}{2}\right)^{15}\)
