Question

(2x-1)²=25

3x²-2x=5(3x-2)

Answer 1

1) \(\left(2x-1\right)^2=25\)

\(\Rightarrow\left[{}\begin{matrix}2x-1=5\\2x-1=-5\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)

2) \(3x^2-2x=5\left(3x-2\right)\)

\(\Rightarrow3x^2-17x+10=0\)

\(\Rightarrow3x\left(x-5\right)-2\left(x-5\right)=0\)

\(\Rightarrow\left(x-5\right)\left(3x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{2}{3}\end{matrix}\right.\)