Ta có: \(\left(2x-1\right)^2=100\)
=>\(\left[\begin{array}{l}2x-1=10\\ 2x-1=-10\end{array}\right.\Rightarrow\left[\begin{array}{l}2x=11\\ 2x=-9\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac{11}{2}\\ x=-\frac92\end{array}\right.\)
Ta có: \(\left(2x-1\right)^2=100\)
=>\(\left[\begin{array}{l}2x-1=10\\ 2x-1=-10\end{array}\right.\Rightarrow\left[\begin{array}{l}2x=11\\ 2x=-9\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac{11}{2}\\ x=-\frac92\end{array}\right.\)
(2X+1)+(2X+2)+.....+(2X+99)+(2X+100)=?
6x.6=2016
42x+3:4=256
[x-2]2=16
[2x-1]3=27
[2x-1]100=[2x-1]100
6x.6=2016
42x+3:4=256
[x-2]2=16
[2x-1]3=27
[2x-1]100=[2x-1]100
1) 3 ( 3x + 2 ) + 2 ( 2x + 4 ) = 90
2) 5 ( x + 1 ) + 3 ( 2x + 1 ) = 65
3 ) 3 ( 4 + 3x ) + 5 ( 1 + 2x ) = 100
Tìm số tự nhiên x biết (2x+1)+(2x+2)+(2x+3)+...+(2x+100)=10050
Bài 6 Tìm x
1) ( x+1 ) + ( x+2 ) + ( x+3 ) + ... + ( x+100 ) = 5750
2) ( 2x-1 ) + ( 4x-2 ) + ... + ( 200x - 100 ) = 5050
3) ( x+2 ) + ( x+4 ) + ( x+6 ) + ... + ( x + 100) = 2650
b)2x+12=3(x+7)
c)2x2-1=49
d)-37-7(2x-1)2=-100
e)-2.(-x-5)+18=20-3.(x+4)
1, -15(x+2)+7(2x-3)=-50
2, x^2-2x=0
3,(-2x)×(-4x)+28=100
Bài 1:Tính tổng
A . 1+(-2)+3+(-4)+...........19+(-20)
B.1-2+3-4+...........99-100
C.1+2-3-4+...........+97+98-99-100
Bài 2:Tìm số nguyên x
-2x-(x-17)=34-(-x+25)
103-57:[-2.(2x-1)2-(-9)0]
-37-7.(2x-1)2 =-100