Question

27x³ - 1

Answer 1

`27x^{3}-1`

`=(3x)^{3}-1^{3}`

`=(3x-1)[(3x)^{2}+3x+1^{2}]`

`=(3x-1)(9x^{2}+3x+1)`

Answer 2

\(27x^3-1=\left(3x\right)^3-1^3=\left(3x-1\right)\left[\left(3x\right)^2+3x\cdot1+1^2\right]=\left(3x-1\right)\left(9x^2+3x+1\right)\)