Ta có : 2 ^ 5 + 12 . ( x ^ 3 - 20 ) = 116
=> 32 + 12 . ( x ^ 3 - 20 ) = 116
=> 12 . ( x ^ 3 - 20 ) = 116 - 32
=> 12 . ( x ^ 3 - 20 ) = 84
=> x ^ 3 - 20 = 84 : 12
=> x ^ 3 - 20 = 7
=> x ^ 3 = 7 + 20
=> x ^ 3 = 27
=> x ^ 3 = 3 ^ 3
=> x = 3
Vậy x = 3
\(2^5+12\left(x^3-20\right)=116\)
\(\Rightarrow32+12\left(x^3-20\right)=116\)
\(\Rightarrow12\left(x^3-20\right)=116-32=84\)
\(\Rightarrow x^3-20=84:12=7\)
\(\Rightarrow x^3=7+20=27\)
\(\Rightarrow x^3=3^3\Rightarrow x=3\)
Vậy \(x=3\)
~ Học tốt ~
\(2^5+12\left(x^3-20\right)=116\)
\(32+12x^3-12\cdot20=116\)
\(32+12x^3-240=116\)
\(32+12x^3=116+240\)
\(32+12x^3=356\)
\(12x^3=356-32\)
\(12x^3=324\)
\(x^3=324\div12\)
\(x^3=27\)
Mà \(3^3=27\)
\(\Rightarrow x=3\)
k cho mình nha☺☺
25 + 12(x3 - 20) = 116
32 + 12(x3 - 20) = 116
12(x3 - 20) = 116 - 32
12(x3 - 20) = 84
x3 - 20 = 84 : 12
x3 - 20 = 7
x3 = 7 + 20
x3 = 27
x3 = 33
=> x = 3
\(2^5+12\left(x^3-20\right)=116\)
\(32+12\left(x^3-20\right)=116\)
\(12\left(x^3-20\right)=116-32\)
\(12\left(x^3-20\right)=84\)
\(\left(x^3-20\right)=84\text{ : }12\)
\(x^3-20=7\)
\(x^3=7+20\)
\(x^3=27\)
\(x^3=3^3\)
\(x=3\)