\(24\cdot\left(x-16\right)=12^2\\ =>24\cdot\left(x-16\right)=144\\ =>x-16=\dfrac{144}{24}\\ =>x-16=6\\ =>x=16+6\\ =>x=24\)
Vậy: ...
\(24\left(x-16\right)=12^2\)
\(x-16=144\div24\)
\(x-16=6\)
\(x=32\)
`x - 16 = 12^2 : 24`
`x - 16 = 144 : 24`
`x - 16 = 6`
`x = 6 + 16`
Vậy `x = 22`