Question

(-2/3x-1).(x^2-4/9)=0

Answer 1

\(\left(-\dfrac{2}{3}x-1\right).\left(x^2-\dfrac{4}{9}\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}-\dfrac{2}{3}x-1=0\\x^2-\dfrac{4}{9}=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}\dfrac{2}{3}x=-1\\x^2=\dfrac{4}{9}=\left(\pm\dfrac{2}{3}\right)^2\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-1:\dfrac{2}{3}=-\dfrac{3}{2}\\x=\pm\dfrac{2}{3}\end{matrix}\right.\)